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CGP EDU Academic Team
Published on: August 14, 2026
What is the charge on the complex [Cr(C2O4)2(H2O)2] formed by Cr( ΙΙΙ )?
Text Solution
Verified by ExpertsThe correct answer is:
D
H2O is neutral, chromium oxidation state i.e. charge is +3 and oxalato anion has –2 charge; due to two C2O42– it will be – 4 and net charge on the complex is algebraic sum of the charge on metal ion and ligands present in the coordination sphere. So 3 + 2 × (–2) = – 1. So the formulae of complex is [Cr(C2O4)(H2O)]–.
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